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Solve a 1-dimensional equation to find the roots. This does alternating secant and bisection steps. It will work for any function, discontinuous or not. For a nasty function, it might be a factor of 2 slower than bisection, but for a nearly-linear function, it can be much faster than bisection.
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Find a root of an equation.
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Find a zero in an array y. This function assumes there is known to be a root in [xl,xh]. It returns a real-number index into the array which linearly interpolates to zero. |
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| Generated by Epydoc 3.0.1 on Thu Sep 22 04:25:02 2011 | http://epydoc.sourceforge.net |